0
$\begingroup$

Assume I want to tag a user in comment to a question in which the User is not involved. Is that possible?

Assume user AAA have asked a question. I am user BBB and I want to comment and tag another user CCC which has nothing to do with the question.

$\endgroup$
3
$\begingroup$

In general, you can't tag users who haven't commented on the post.

From the FAQ: How do comment @replies work?

Who can be notified with this feature?

  • The author of the post.

    Note that the author of the post will always be notified of any new comment. You may still use it for clarity, if needed; however if only you and the author have commented on the post so far, the @name will be automatically removed from the beginning of the comment, as it adds no value.

  • Any user who has a visible (non-deleted) comment on the post.

    Note that if a user comments on their own post and there is only one other person who has previously commented on that post, then that person is also notified, even if @name is not used.

Keep in mind that the question and answers are all considered independently. For example, if Alice was the author of the question, then you cannot notify her by commenting on Bob's answer (unless Alice also participated in that answer). Similarly, you cannot notify Bob by commenting on Alice's question.

However, there are some exceptions where you still can tag them:

  • Any user who has edited the post (does not include pending or rejected edit suggestions).

  • For questions: The moderator or gold badge holder who closed or reopened the question, provided they were the only one to do so. Users who have closed or reopened a question without a binding close vote (i.e. without a gold tag badge or a moderator vote), and those who bindingly voted, but other users were also involved (e.g. closed by User1, User2, and Moderator) cannot be notified.

  • For questions: any user who set a bounty on the question (current or expired)

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .